Respuestas

2012-10-30T15:52:26+01:00

sen(90+x)= sen90 cos x + cos90 senx = 1 cosx + 0 senx = cos x

sen(360-x) = sen360 cos x - cos360 senx = 0 cosx - 1 senx = -senx

cos(180-x) = cos 180 cos x + sen 180 sen x = (-1)cos x + 0 senx = -cos x

cos(270-x) = cos 270 cos x + sen 270 sen x = 0 cos x + (-1)senx = -sen x

 

[(cos x)/(-cos x)] + [(-senx)/(-senx)]= [-1] + [-1] = -2

 

 

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