Respuestas

2012-10-17T01:46:49+02:00

f(x) = 3/(x²+3)²

 

f´(x) = ((3)´·(x²+3)² - (3)·[(x²+3)²]´)/ (x²+3)⁴

 

f´(x) = (0 · (x²+3)² - 3 · [2(x²+3) + 2x]) / (x²+3)⁴

 

f´(x) = (-3 · [2x²+6+2x]) / (x²+3)⁴

 

 f'(x) = \frac{-6x^{2}-6x-18}{(x^{2}+3)^{4}}