Respuestas

2012-10-01T05:48:21+02:00
2012-10-01T05:52:11+02:00

primer: (2/9)x

segundo: (3/5)(1-2/9)x= (3/5)(7/9)x

tercero: (4/7)(2/5)(7/9)x

cuarto: 300 = (3/7)(2/5)(7/9)x

resolviendo:

3*2*7x           6x
-----  = 300 => ---- = 300 => x= 300*45/6 = 2250
7*5*9            45

 


al tercero le toca:

 4*2*7x    8x   8*2250
------- = ----= ------- = 400
 7*5*9     45     45