Respuestas

2012-09-15T07:23:11+02:00

x^2+2yz=√7-√2...(1)

z^2+2xz=2-√7...(2)

y^2+2xy=2+√2...(3)

sumando(1)+(2)+(3)

x^2+2yz+z^2+2xz+y^2+2xy=√7-√2+2-√7+2+√2

x^2+y^2+z^2+2xy+2xz+2yz=4

(x+y+z)^2=4

x+y+z=2