Respuestas

2012-09-12T07:00:51+02:00

facil

triangulo de pascal

1                      1

2                    1 2 1

3                  1 3  3  1  

4                 1 4 6  4  1

5                1 5 10 10 5 1

6               1 6 15 20 15 6 1

7             1 7 21 35 35 21  7 1

8          1  8  28  56 70 56 28 8 1

 

Luego:

 

(a^e-1)^8=1(a^e)^8-8(a^e)^7+28(a^e)^6-56(a^e)^5 +70(a^e)^4 -56(a^e)^3

                +28(a^e)^2-8(a^e) +1

(2+c)^7=  2^7+ 7(2^6)*c +21(2^5)*(c^2)+ 35(2^4)*(c^3)+ 35(2^3)*(c^4)+     21(2^2)*(c^5) + 7(2)(c^6)+ (c^7)