Respuestas

2012-09-12T05:59:05+02:00

lim       (sen(x)-sen(π/2))/(x-π/2)

x-->π/2

u=x-π/2

x->π/2 entonces u-->0

lim       (sen(u+π/2)-sen(π/2))/(u+π/2-π/2)

u-->0

lim   (cosu-1)/u=

u-->0

lim   (cosu-1)/u=lim   (cosu-1)(cosu+1)/(u(cosu+1))

u-->0                 u-->0

lim  -sen^2u/(u(cosu+1))=-lim   ( senu/u)lim(senu)/((cosu+1))=-1(0)=0

u-->0                                  u-->0            u-->0

esa es la respuesta