Respuestas

2012-09-09T07:28:27+02:00

Let u = x²
du = 2x dx
dv = e^(5x) dx
v = (1/5) e^(5x)

∫udv = uv - ∫vdu

∫x²e^(5x) dx = (1/5) x² e^(5x) - 2/5∫ x e^(5x) dx

du = dx
dv = e^(5x) dx
v = (1/5) e^(5x)

- 2/5∫ x e^(5x) dx = (-2/5) [(1/5) x e^(5x) - (1/5)∫e^(5x) dx] =
(-2/5) [(1/5) x e^(5x) - (1/5)(1/5) e^(5x)] =

-(2/25) x e(5x) + (2/125) e^(5x)



(1/5) x² e^(5x) - (2/25) x e(5x) + (2/125) e^(5x) + C BUENO ESOS SON