Respuestas

2012-08-31T02:03:11+02:00

5^(4x-3)=2^(2x-9)

 

log[5^(4x-3)]=log[2^(2x-9)]

(4x-3)log5=(2x-9)log2

 

(4x-3)  =   log5  =0.431

(2x-9)       log2

 

(4x-3)  = 0.431(2x-9)

(4x-3) = 0,862x-3.879

3.138x=3-3.789

3.138x =0.789

x= 0.789/3.138

x=0.25143