Respuestas

2012-07-16T20:11:08+02:00

La derivada es:

f'(x) = (5x^{4}+9x^{2}+5)(4x^{3}-2x+1) + (x^{5}+3x^{3}+5x-2)(12x^{2}-2)

 

y en f(0)

 

f'(0) = (5*0^{4}+9*0^{2}+5)(4*0^{3}-2*0+1)

 + (0^{5}+3*0^{3}+5*0-2)(12*0^{2}-2)

 

f'(0) = 5 + (-2)(-2)

f'(0) = 9

 

espero te sirva....