Respuestas

2012-07-06T21:52:16+02:00

-\frac{9}{2}x ( 3x -\frac{2}{3}x +1) -2 =\frac{5}{3}x +5

 

-\frac{9}{2}x (\frac{7}{3}x +1) -2 =\frac{5}{3}x +5

 

-\frac{9}{2}x (\frac{7}{3}x) -\frac{9}{2}x -2 -\frac{5}{3}x -5 = 0

 

-\frac{63}{6}x^2 -\frac{37}{6}x -7 = 0

 

(-\frac{63}{6}x^2 -\frac{37}{6}x -7 = 0 ) -6

 

63}x^2 +37x +42 = 0

 

Apartir de aui podemos intentar factorizar o aplicar la formula general