Respuestas

2012-06-17T20:45:55+02:00

1 +x +\frac{4}{6}-5x +\frac{2}{12} +\frac{3(x-2)}{4} = 2

 

1 +\frac{2}{3} +\frac{1}{6} - 4x +\frac{3}{4}x -\frac{6}{4} = 2 

 

 1 +\frac{2}{3} +\frac{1}{6} -\frac{3}{2} -4x +\frac{3}{4}x = 2 

 

\frac{6 + 4+1-9}{6} - (\frac{16x +3}{4}) = 2

 

\frac{1}{3} -\frac{19}{4}x =2

 

-\frac{19}{4}x = 2 -\frac{1}{3}

 

x = \frac{5}{3} /\frac{19}{4}

 

x = \frac{20}{57}