Respuestas

  • Usuario de Brainly
2014-02-17T16:07:45+01:00
2x^2 -32 =0
2^2 =32
x^2 =32/2
x^2 = 16
√x^2 =√16
x = 4
x=-4    solucion = (4, -4)

x²=x
x^2 -x =0
x(x-1) =0
x=0
x-1=0 entonces x =1  solucion = (0, 1 )

6ײ=-12×
6x^2+12x =0
6x(x +2)=0
6x = 0  entonces x=0/6 =0
x+2 = 0 entonces x= -2  solucion = (0, -2)