Respuestas

2014-01-21T23:44:20+01:00
\frac{a}{b}=\frac{c}{d}=K

\frac{a+c}{b+d}=\frac{3}{2}

a+b=35

c+d=45

a = bK
c = dK

\frac{bK+dK}{b+d}=\frac{3}{2}

\frac{K(b+d)}{b+d}=\frac{3}{2}

K=\frac{3}{2}

a+b = 35 => bK+b = 35 => b(K+1)=35 pero K = \frac{3}{2}

b(\frac{3}{2}+1)=35

b =\frac{35*2}{5}= 14

c+d = 45 => dK+d = 45 => d(K+1)=45 pero K = \frac{3}{2}

d(\frac{3}{2}+1)=45

d =\frac{45*2}{5}= 18
 entonces c = 27

luego b + c = 14 +27 = 41