Respuestas

2013-12-09T07:27:47+01:00
\frac{log(x-7)}{log(x-1)} = 0.5\\
log_{x-1}(x-7) = 0.5\\
(x-1)^{\frac{1}{2}} = x-7\\
x-1 = (x-7)^{2}\\
x-1 = x^{2} -14x+49\\
x = 50-14x+x^{2}


ahora hay que usar la fórmula de bascara

x_{1} = 7\\
x_{2} = 7