Respuestas

  • Usuario de Brainly
2013-11-21T05:15:34+01:00

1)

log[2+log2[log4(a-4)-3/2]=0

log[2+log2[log4(a-4)-3/2]= log 1

 2 + log2[log4(a-4)-3/2] =  1

     log2[log4(a-4)-3/2]  = -1
 
         2[log4(a-4) -3/2] = 10^-1
            
  log (4(a-4))² - 3  = 0,1
       
          log (16a - 256) = 3,1
 
              16a-256 = 10^3,1
                   
               16a = 1256,266
 
                   a = 78,52 aprox


2)

logx+log50=3
 log 50x = 3

50x = 10^3
    x = 1000/50
    x = 20