Respuestas

2013-11-05T18:21:55+01:00
D(x) = 3x^2 + 2x + 1
Q(x) = 0'1
R(x) = - 4

[D(x) · Q (x)] + R (x)

[D(x) · Q (x)] = 
= [ 3x^2 + 2x + 1 ] · 0'1 =  
= 0'3x^2 + 0'2x + 0'1 

[D(x) · Q (x)] + R (x) = 
= [ 0'3x^2 + 0'2x + 0'1 ] + (-4) = 
=  0'3x^2 + 0'2x - 3'9