Respuestas

2013-11-07T21:25:21+01:00
log(x-2) + log5 = 1 - log(x-3)

lg ( x-2 ) . 5 = lg 10 - lg ( x-3)

lg ( x-2) .5 = lg 10 / x-3

(x-2 ) .5 = 10 / x-3

5x - 10 = 10 / x-3 

5x ( x-3 ) -10 ( x-3 ) = 10

5x^2 -15x -10x + 30 = 10

5x^2 -25x + 20 = 0

simplificando dividiendo por 5 queda 

x^2 -5x + 4 = 0


5±√5^2 -4. 4 
------------------  =       soluciones x1 =  4      x2 = 1
       2