Respuestas

2012-05-20T00:42:07+02:00

16^X+64=20*2^X

LOG(16^X+64)=LOG(20*2^X)

log(16^x)+log64=20log(2^x)

xlog(16)+log64=20xlog(2)

xlog(16)-20xlog(2)=-log64

x(log16-20log2)=-log64

x=(-log64)/(log16-20log2)

x=3/8