Respuestas

2012-01-09T01:30:01+01:00

n..........6

n-2........4

n+2.........8

 

(n+2)^{2}-[n^{2}+(n-2)^{2}]=12

(n)^{2}+4n+4-[n^{2}+(n)^{2}-4n+4]=12

n^{2}-8n+12=0

(n-2)(n-6)=0

n=2

n=6