Respuestas

2013-07-23T17:17:31+02:00
0.5 M = moles soluto / v (L) disolucion
0.5 M = x / 0.1 L
x = 0.5 × 0.1
x= 0.05 moles soluto
PM (Na2CO3) -> 2×23+1×12+3×16
46 + 12 + 48
PM = 106 g / 1 mol
106g / 1 mol = x g / 0.05 moles
1x = 106 × 0.05
x = 5.3 g Na2CO3