Respuestas

2012-04-26T02:23:42+02:00

ocuparé la notación \overrightarrow C = \left( {x,y} \right) = \left( {\begin{array}{*{20}c} x \\ y \\ \end{array} } \right)

 

Se tiene que:

 

\overrightarrow {AB} = \overrightarrow {OA} + \overrightarrow {OB} = \left( {\begin{array}{*{20}c} {1 + 9} \\ {4 + 8} \\ \end{array} } \right) = \left( {\begin{array}{*{20}c} {10} \\ {12} \\ \end{array} } \right)

 

Entonces:

 

\dfrac{{\overrightarrow {AB} }} {2} = \left( {\begin{array}{*{20}c} {\dfrac{{10}} {2}} \\ {\dfrac{{12}} {2}} \\ \end{array} } \right) = \left( {\begin{array}{*{20}c} 5 \\ 6 \\ \end{array} } \right)

 

Saludos