Respuestas

  • Usuario de Brainly
2013-05-30T01:49:42+02:00
Aplicaremos definición
loga B = c  si y solo si      a^c = B
entonces
log16 X = -3/4 →  16^(-3/4) = x → 1/8 = x

log2 X = - 1/3 → 2^(-1/3) = x → 0.79 = x

log8 X = 5 → 8^5 = x → 32768 = x

xlogx³ = x → logx³ =x/x →10^1 = x³ →³√10 = x → 2.15 = x

log6x= -1 → 6^-1= x → 1/6 = x

log16 x = -3/2 → 16^(-3/2) = x→ 1/64 = x

x = log2 (1/16) → x = -4

espero que te sirva,salu2!!!!