Respuestas

2013-03-31T23:15:54+02:00

s: (x - 2)/3 = y/(-2) => y = (-2/3)(x - 2) => y = (-2/3)x + 4/3
s: (x + 5)/(-6) = (y - 1)/k => y =[k/(-6)](x + 5) + 1 => y = (-k/6)x + [-5k/6 + 1
Para que las rectas sean paralelas deben tener igual pendiente, entonces:
-2/3 = -k/6
k = (2/3)*6
k = 4