Respuestas

2012-12-06T22:31:49+01:00

derivando toda la ecuacion

 

3((x-y)^2)(1-y')-2y-2xy'+4x^3=0

y'[-3(x-y)^2-2x]=-3(x-y)^2+2y-4x^3

 

y'=[3(x-y)^2+2y-4x^3]/[-3(x-y)^2-2x]