Respuestas

2012-12-06T18:53:28+01:00

0=\frac{2-2}{2+2+2}=\frac{0}{6}\\1=\frac{2-2}{2}+\frac{2}{2}=0+1\\ 2=2+2+2-2-2=6-4\ o\ 2=\frac{2-2}{2+2}+2=0+2\\ 3=2+\frac{2+2}{2+2}=2+1\\
4=2+2+\frac{2-2}{2}=4+0\ o\ 4=\frac{2+2+2+2}{2}=4\\ 5=\frac{2}{2}+2+\frac{2\cdot2}{2}=1+2+2\\ 6=2+2+2+2-2=8-2\\ 7=\frac{2}{2}+2+2+2=6+1 \\ 8=\frac{2\cdot2}{2}+2+2+2=2\cdot5 \\ 9=2\cdot2\cdot 2+\frac{2}{2}=8+1
10=2+2+2+2+2\\ 11=(2+\frac{2}{2})^2+2=3^2+2=9+2\\ 12=(2\cdot2)^2-2^2=16-4\\


Ahí esta, el 11 costo, pero se pudo :D

2012-12-06T21:05:49+01:00

0 =2-2/2-2/2

1 =(2-2)/2 + 2/2

2 =2- 2- 2 +2 +2

3 =(2+2)/(2+2) +2

4 =(2-2)/2 +2+2

5 =2/2 + 2/2 + 2

6 =2 + 2+2 +2 -2

7 = 2 +2 +2 +2/2

8 = 2 +2 (2+2)/2 +2

9 = 2 x2 x2 +2/2

10= 2+2+2+2+2



listo